Find the equation of a line, in slope-intercept fotm of a line that passes through the point (9,2) and is perpendicular to the line 2x-y=8

Respuesta :

Considering the definition of perpendicular line, the equation of of perpendicular line is y= -[tex]\frac{1}{2}[/tex]x + [tex]\frac{13}{2}[/tex].

Linear equation

A linear equation o line can be expressed in the form y = mx + b.

where

x and y are coordinates of a point.

m is the slope.

b is the ordinate to the origin and represents the coordinate of the point where the line crosses the y axis.

Perpendicular line

Perpendicular lines are lines that intersect at right angles or 90° angles. If you multiply the slopes of two perpendicular lines, you get –1.

Equation of perpendicular line in this case

In this case, the line is 2x-y=8. Expressed in the form y = mx + b, you get:

-y=8 - 2x

y= (-2x +8)÷ (-1)

y= 2x -8

If you multiply the slopes of two perpendicular lines, you get –1. In this case, the line has a slope of 2. So:

2× slope perpendicular line= -1

slope perpendicular line= (-1)÷ (2)

slope perpendicular line= -[tex]\frac{1}{2}[/tex]

So, the perpendicular line has a form of: y= -[tex]\frac{1}{2}[/tex]x + b

The line passes through the point (9, 2). Replacing in the expression for perpendicular line:

2= (-[tex]\frac{1}{2}[/tex])× 9 + b

2=  -[tex]\frac{9}{2}[/tex] + b

2+ [tex]\frac{9}{2}[/tex]= b

[tex]\frac{13}{2}[/tex]= b

Finally, the equation of of perpendicular line is y= -[tex]\frac{1}{2}[/tex]x + [tex]\frac{13}{2}[/tex].

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