Respuesta :
The work done is 1350. Option C is correct. The work-energy theorem is applied to a given problem.
What is the work-energy theorem?
From the work-energy theorem, it is stated that the net work done is equal to the change in the kinetic energy.
[tex]\rm W_{net}=K_f-K_i \\\\ \rm W_{net}=\frac{1}{2}mv_f^2-\frac{1}{2} mv_i^2 \\\\ W_{net}=\frac{1}{2} m(v_f^2-v_i^2)}[/tex]
Substitute the given value;
[tex]\rm W_{net}=\frac{1}{2} \times 60 \times (9.00^2-6.00^2)} \\\\ W_{net}=1350 \ J[/tex]
The work done is 1350 J.
Hence option C is correct.
To learn more about the work-energy theorem, refer to the link;
https://brainly.com/question/16995910
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