Given that KL/KM = KP/KN = PL/MN = k, m∠K = m∠K, m∠L = m∠M and m∠P = m∠N, then by SAS theorem we conclude that ΔLKP ∼ ΔMKN.
How to define the similarity between the two triangles
By Euclidean geometry we know that two triangles are similar when the two triangles have the same angles in the same order. Thus, the sides between the two triangles have the same proportionality, then:
KL/KM = KP/KN = PL/MN
Given that KL/KM = KP/KN = PL/MN = k, m∠K = m∠K, m∠L = m∠M and m∠P = m∠N, then by SAS theorem we conclude that ΔLKP ∼ ΔMKN.
To learn more on similar triangles: https://brainly.com/question/25882965
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