Respuesta :
The age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.
What is the half-life of a radioactive material?
The half-life of a radioactive material is the time taken for half the atoms present in the material to decay or disintegrate.
The half-life, [tex]t_\frac{1}{2}[/tex], the age, t, and amount remaining, [tex]A_{r}[/tex], of a radioactive material are related by the formula below:
- [tex]t = \frac{t_\frac{1}{2}*A_{r}}{-ln2}[/tex]
Half-life of carbon-14 = 6000 years
For the Egyptian papyrus with 63% of its original carbon-14 atoms:[tex]t = \frac{6000*0.63}{-0.63} = 4000\:years[/tex]
For the Aboriginal charcoal with 22% of its original carbon-14 atoms:
[tex]t = \frac{6000*0.22}{-0.63} = 13106.5\:years[/tex]
For the Mayan headdress with 79% of its original carbon-14 atoms:
[tex]t = \frac{6000*0.79}{-0.63} = 2040\:years[/tex]
Neanderthal skull with 3% of its original carbon-14 atoms:
[tex]t = \frac{6000*0.03}{-0.63} = 30353\:years[/tex]
Therefore, the age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.
Learn more about half-life at: https://brainly.com/question/26689704
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