According to a recent survey, the salaries of entry-level positions at a large company have a mean of and a standard deviation of . Assuming that the salaries of these entry-level positions are normally distributed, find the proportion of employees in entry-level positions at the company who earn at least . Round your answer to at least four decimal places.

The Gaussian distribution is another name for it. The most significant continuous probability distribution is this one. Because the curve resembles a bell, it is also known as a bell curve.

According to a recent survey, the salaries of entry-level positions at a large company have a mean of $ 41,750 and a standard deviation of $ 6500.

Assuming that the salaries of these entry-level positions are normally distributed.

Then the proportion of employees in entry-level positions at the company who earn at least $ 42,000 will be

The z-score is given as

z = (x - μ) / σ

Then we have

z = (42000 - 41750) / 6500

z = 0.03846

Then we have

P(x ≥ 42000) = P(z ≥ 0.03846)

P(x ≥ 42000) = 1 - P(z < 0.03846)

P(x ≥ 42000) = 1 - 0.51534

P(x ≥ 42000) = 0.48466

More about the normal distribution link is given below.

https://brainly.com/question/12421652

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