If a mixture containing 0.50 moles of N2 and 1.8 moles of H2 is allowed to react according to the equation N2 3H2 2NH3 Group of answer choices N2 is the limiting reactant. Both A and B are correct. H2 is the limiting reactant. 34.0 grams of NH3 can be produced.

Respuesta :

Answer: hydrogen is the limiting reactant.

Explanation:

We have the equation [tex]\text{N}_{2}+3\text{H}_{2} \longrightarrow 2\text{NH}_{3}[/tex].

This means that for every mole of nitrogen consumed, 3 moles of hydrogen are consumed.

  • Considering the nitrogen, the reaction can occur 0.50 times.
  • Considering the hydrogen, the reaction can occur 1.8/3 = 0.6 times.

Therefore, hydrogen is the limiting reactant.