If the concentration of the product NH3 was increased from 1.0 x 10-4 M to 5.6 x 10-3 M, calculate the reaction quotient (Q) and determine which way the chemical system would shift by comparing the value of Q to K.

Respuesta :

The chemical system will shift to the left in order to produce more N₂ , H₂.

The missing data in the question is

The equilibrium constant (K) of the reaction below is K = 6.0 x 10⁻² with initial concentrations as follows: H₂ = 1.0 x 10⁻² M, N₂ = 4.0 M, and NH₃ = 1.0 x 10⁻⁴M.

What is Chemical Equilibrium?

When the rate of forward reaction is equal to the rate of the backward reaction then the equation is said to be in Chemical Equilibrium.

N₂ + 3H₂ --> 2NH₃

The reaction quotient, Q, has the same algebraic expressions but uses the actual concentrations of reactants.

[N₂] = 4.0M; [NH₃] = 1.0x10⁻⁴M and [H₂] = 1.0x10⁻²M

Thus, for the reaction:

N₂ + 3H₂ ⇄ 2NH₃

The equilibrium constant, K, of this reaction, is defined as:

[tex]\rm K = \dfrac{[NH_3]^2}{[H_2]^3 [N_2]}[/tex]

[tex]\rm Q = \dfrac{[NH_3]^2}{[H_2]^3 [N_2]}[/tex]

Q = (5.6 x 10⁻³ )² / (1.0 x 10⁻²) ³(4.0 )

Q = 7.84

As Q > K,

The chemical system will shift to the left in order to produce more N₂ , H₂

To know more about chemical equilibrium

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