0.164 g/L is the density of a sample of 1.00 mole of [tex]NH_3[/tex] at 793mmhg and -9.00 degrees celcius.
Density is the mass of a unit volume of a material substance. The formula for density is d = [tex]\frac{M}{V}[/tex], where d is density, M is mass, and V is volume.
Given data:
n = 1.00 mole
P=793 mm hg =1.04342 atm
T=-9.00 degree celcius = -9.00 + 273= 264 K
V=?
Using Ideal Gas Law equation:
PV = n R T
R = gas constant = 0.082057 L-atm/(mol-K)
(1.04342 atm)(V) = 5 X 0.082057 L-atm/(mol-K) X 264 K
V = 103.67 Liters
Now calculate density:
Mole weight of [tex]NH_3[/tex] = 1.00 mole
So, the mass of [tex]NH_3[/tex] = 17.031 g
Density = [tex]\frac{mass}{volume}[/tex]
Density = [tex]\frac{17.031 g}{ 103.67 Liters}[/tex]
= 0.164 g/L
Hence, 0.164 g/L is the density of a sample of 1.00 mole of [tex]NH_3[/tex] at 793mmhg and -9.00 degrees celcius.
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