Answer:
Chemical Formula of propane C3H8, mole mass (C)12*3+(H)1*8=44 g (1 mole)
44 g also corresponds molar volume 22,4 l
36 g from 44 g is 81% of 1 mole
Avogadro Constant is N = (6,0230 + 0,0002) 1023x ~602000000000000000000000 the quantity of molecules in 1 mole
Quantity of molecules in 36 g (6,0230 + 0,0002) 1023x * 0,81
~487620000000000000000000
Quantity of atoms 487620000000000000000000 * 11 (why eleven? because every molecule of propane consists of 11 atoms 3 -carbon and 8-hydrogen = 3+8 =11)
So, ~5 363 820 000 000 000 000 000 000 is quantity of atoms in 36 g of propane.
