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A stone is thrown with an initial speed of 15 m/s at an angle of 53° above the horizontal from the top of a 35 m building. If g = 9.8 m/s2 and air resistance is negligible, what is the magnitude of the horizontal displacement of the rock?

Respuesta :

The horizontal displacement of the rock is 18. 18 m

How to determine the horizontal displacement?

Using the formula:

Horizontal displacement = Vo^2 * sin 2θ /g

Where V0 = initial speed = 15m/s

θ = 53°

g = 9. 8m/s²

Substitute values into the formula

Horizontal displacement = 15 * 15 * sin 2 (53°) / 9. 8

Horizontal displacement = 225 * 0. 7919/ 9.8 = 225 * 0.0808

Horizontal displacement = 18. 18 m

Therefore, the horizontal displacement of the rock is 18. 18 m

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