Respuesta :

  • The equivalent capacitance between point a and b is 5.87μf.
  • The charge at 20μf is 93.92 μC.
  • The charge at 6μf is 67.8 μC.
  • The charge at C and 3μf is 26.12 μC.

Sum of capacitance of C and 3μF

The sum of the capacitance is calculated as follows;

1/Ct = 1/C + 1/3

1/Ct = 1/10μf + 1/3μf

1/Ct = (3μf + 10μf)/30μf²

1/Ct = 13μf/30μf²

Ct = 30μf²/13μf

Ct = 2.31μf

Total capacitance in parallel arrangement

The total capacitance in parallel arrangement is calculated as follows;

Ct = 2.31μf + 6μf = 8.31μf

Equivalent capacitance between point a and b

1/Ct = 1/8.31μf + 1/20μf

1/Ct = 0.1703

Ct = 5.87μf

Charge flowing in each capacitor

Maximum voltage is delivered in 20μf, q = CV

charge for 20μf:

q = (5.87 x 16)μC

q = 93.92 μC

Equivalent capacitance for C, 3μf and 6μf

Ct = 2.31μf + 6μf = 8.31uf

charge for 6μf:

q = (6/8.31) x 93.92μC

q = 67.8μC

Total charge for C and 3μf

q = 93.92μC - 67.8μC = 26.12 μC

charge for C = charge 3μf = 26.12 μC

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