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Find \displaystyle \lim_{x\to 1}f(x)
x→1
lim
​
f(x)limit, start subscript, x, \to, 1, end subscript, f, left parenthesis, x, right parenthesis for f(x)=\sqrt{51-2x}f(x)=
51−2x
​
f, left parenthesis, x, right parenthesis, equals, square root of, 51, minus, 2, x, end square root.

Respuesta :

loneguy

[tex]\lim \limits_{x \to 1} \sqrt{51 -2x}\\\\=\sqrt{51 -2 (1)}\\\\=\sqrt{51-2}\\\\=\sqrt{49}\\\\=7[/tex]

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