Required Answer
[tex] \dashrightarrow \: \bf{Solution}[/tex]
Given that,
[tex] \sf(3x - 1)(x + p) = 3 {x}^{2} + qx - 5[/tex]
So yea' let's begin!
[tex] \sf \longrightarrow \sf \: 3 {x}^{2} + 3xp - x - p = 3 {x}^{2} + qx - 5[/tex]
Here, 3x² will be cancelled out!
[tex] \sf \longrightarrow \: 3x(p - 1) - p = qx - 5[/tex]
[tex]\sf \longrightarrow \: [3(p - 1)]x \: - p = qx - 5[/tex]
On comparing ~
[tex] \sf \twoheadrightarrow\bf \: q = \red{3(p - 1)}[/tex]
[tex] \bf \twoheadrightarrow \: p = \blue{ 5}[/tex]
[tex] \sf[/tex]
[tex] \rule{200pt}{2pt}[/tex]
