please solve it ASAP

The Estimated thickness of the condensate film is 0.09mm.
Given:
L=1m
Surface temperature =117°C
Properties of steam at p=2.45 bar
Hence:
T sat =126.7°C
h f g =2183.5×10³J/kg
Mean temperature, T f=126.7+117÷2
T f =121.85°C
Properties of water at T f=121.85°C are:
p=943kg/m³
u=237×10^-6 kg/ms
k f=0.686W/m. K.
Thickness of condensate at x=0.2m
=[4kf (Tsat-Ts) ux÷p(p-pv)gh fg]^1/4
Neglect pv and from the formula
[4×0.686×(126.7-117)×237×10^-6×0.2÷(943)²×9.81×2183.5×10³]^1/4
=9.02×10^-5
=0.09mm
Therefore the Estimated thickness of the condensate film is 0.09mm.
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