Answer:
see explanation
Step-by-step explanation:
sinG = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{HI}{GI}[/tex] = [tex]\frac{2}{2\sqrt{2} }[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex] = [tex]\frac{\sqrt{2} }{2}[/tex]
cosG = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{GH}{GI}[/tex] = [tex]\frac{2}{2\sqrt{2} }[/tex] = [tex]\frac{1}{\sqrt{\sqrt{2} } }[/tex] = [tex]\frac{\sqrt{\sqrt{2} } }{2}[/tex]
tanG = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{2}{2}[/tex] = 1
