The factored expression of 2n^2 + 18n + 28 is (2n + 14)(n + 2)
How to factor the expression?
The expression is given as:
2n^2 + 18n + 28
The above expression is a quadratic expression represented as:
an^2 + bn + c
This means that
a = 2, b = 18 and c = 28
So, the answer to the questions are:
- Yes, there is a GCF
- The value a is 2
- The two numbers to be added are 14 and 4
The factor of the expression is the represented as:
2n^2 + 18n + 28 = 2n^2 + 2n + 14n + 28
Factorize
2n^2 + 18n + 28 = 2n(n + 2) + 14(n + 2)
Factor out n + 2
2n^2 + 18n + 28 = (2n + 14)(n + 2)
Hence, the factored expression of 2n^2 + 18n + 28 is (2n + 14)(n + 2)
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