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The distance between the points M and N is equal to R · (1 - cos θ/2). (Correct choice: B) In addition, the distance between the points P and Q is equal to 348.683 feet.
In this question we have a geometrical system formed by a circular section and four right triangles. The distance between the points M and N is found by the following subtraction and subsequent trigonometric expressions:
MN = OM - ON
MN = R - R · cos θ/2
MN = R · (1 - cos θ/2)
And the distance between the points P and Q is found by the following trigonometric expression:
d = PN/cos θ/2
d = (R · sin θ/2)/cos θ/2
d = R · tan θ/2
d = (958 ft) · tan 20°
d ≈ 348.683 ft
To learn more on trigonometry: https://brainly.com/question/26719838
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