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2- An instrument has resistance of 7 Ohms. its moving coil gives full deflection with 25 mA If a resistance of 0.7 Ohms is connected in parallel with the instrument, the instrument will be capable of reading up to A- 0.275 A B- 0.280 A R= V- 17- r C- 0.295 A 크 0175 25X163 7 D- 0.297 A I -0.179​

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pstnonsonjoku

From the calculation, the instrument will have a full scale deflation at 0.225A.

What is a shunt?

We can convert a galvanometer to an ammeter by connecting a shunt resistance in parallel.

The current that flows across the shunt = I

Thus;

0.70I = 0.025 * 7

I = 0.25 A

0.25 A - 0.025 A =0.225A

Learn more about galvanometer:https://brainly.com/question/17247518

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