LM is the line perpendicular to a line that has a slope of negative five-sixths.
The missing data in the question is
Line L M goes through (negative 5, negative 3) and (0, 3). Line N O goes through (negative 6, negative 5) and (0, 0). Line J K goes through (negative 6, 1) and (0, negative 4). Line P Q goes through (negative 5, 4) and (0, negative 2). Which line is perpendicular to a line that has a slope of Negative five-sixths? line JK line LM line NO line PQ
The missing image is attached with the answer.
A linear function is what can be represented by a straight line , equation given by y = mx +c .
If a line is perpendicular to other line the product of their slope is equal to -1
The slope of the line = -5/6
The slope of the required line = 6/5
The slope of all the line needs to be determined.
The slope m = (y₂-y₁)/ (x₂-x₁)
Slope of line PQ = -6/5
Slope of line JL = -5/6
Slope of line LM = 6/5
Slope of line NO = 5/6
We needed the slope to be 6/5 , which is of LM to JL
Therefore LM is the line perpendicular to a line that has a slope of negative five-sixths.
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