From the stoichiometry of the reaction, we can see that the volume of carbon monoxide reacted is 44.8 L.
What is stoichiometry?
Stoichiometry is used to obtain the amount of substance reacted or the amount of product formed.
Number of moles of CO2 in 88g = 88g/4 g/mol = 2 moles
Molar mass of carbon monoxide = 12 + 16 = 28g/mol
We can see that 1 mole of oxygen was used in the reaction hence the mass of oxygen used is 32 g/mol. Given the stoichiometry of the reaction, 28g of carbon monoxide was burned.
If 1 mole of a gas occupies 22.4 L
2 moles of a gas occupies 2 moles * 22.4 L/1 mole
= 44.8 L
Learn more about stoichiometry:https://brainly.com/question/9743981
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