[tex](\stackrel{x_1}{5}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{5})[/tex]
Answer:
Step-by-step explanation:
y-y1=m(x-x1)
y-1=1/3(x-5)
Hope this helps!
If not, I am sorry.