The measure of BD, AD, BC and AB are 3.464, 6, 4 and 4√3 respectively
Triangular altitude theorem
Triangle is a shape with 3sides and angles. To determine the value of BD, we will use the SOH CAH TOA identity
tan 60 = BD/2
BD = 2 tan 60
BD = 3.464
Using the triangular altitude theorem to find AD
2/BD = BD/AD
2/3.464 =3.464/AD
AD = 12/2
AD = 6
Determine the measure of BC
BC² = BD² + CD²
BC² = 3.464² +2²
BC² = 12 + 4
BC = 4
Similarly;
AB² = BD² + AD²
AB² = 3.464² +6²
AB² = 12 + 36
AB² = 48
AB = 4√3
Hence the measure of BD, AD, BC and AB are 3.464, 6, 4 and 4√3 respectively
Learn more on triangle altitude theorem here: https://brainly.com/question/14357999?source=archive
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