The cube root of 60 is 3.87 approximately.
Step by step solution:
We can calculate the cube root by Halley's method:
The formula is [tex]\sqrt[3]{a} = x ((x^{3} + 2a)/(2x^{3} + a))[/tex]
where,
a = number whose cube root is being calculated
x = integer guess of its cube root.
Here a = 60,
Suppose x as 3
[∵ 3³ = 27 and 27 is the nearest perfect cube that is less than 60]
⇒ x = 3
Therefore,
∛60 = 3 (3³ + 2 × 60)/(2 × 3³ + 60)) = 3.87
⇒ ∛60 ≈ 3.87
Therefore, the cube root of 60 is 3.87 approximately.
Here , ∛60 is irrational because it cannot be expressed in the form of p/q where q ≠ 0.
Therefore, the value of the cube root of 60 is an irrational number.
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