The probability that the number of spoiled eggs among the 3 selected is 2 will be 0.57.
The probability of favorable events to the total number of occurrences.
A really bad carton of 7 eggs contains 5 spoiled eggs. An unsuspecting chef picks 3 eggs at random for his "Mega-Omelet Surprise".
Then the probability that the number of spoiled eggs among the 3 selected is 2 will be
The total number of the event will be
Total = ⁷C₃
Total = 35
Then the probability will be
P = (⁵C₂ x ²C₁) / 35
P = 10 x 2 / 35
P = 20 / 35
P = 0.57
More about the probability link is given below.
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