Simplify 5 x times the square root of quantity 3 x end quantity minus 2 x times the square root of quantity 3 x end quantity minus x times the square root of quantity 3 x end quantity period.

Answer:
[tex]2x\sqrt{3x}[/tex]
Step-by-step explanation:
They're all multiple of [tex]x\sqrt{3x}[/tex] so we can add likewise terms - the way we do with normal polynomials:
[tex]5x\sqrt{3x}-2x\sqrt{3x}-x\sqrt{3x} = 2x\sqrt{3x}[/tex]