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Enter balanced complete ionic and net ionic equations for each reaction.

HCl(aq)+LiOH(aq)→H2O(l)+LiCl(aq)

CaS(aq)+BaCl2(aq)→BaS(s)+CaCl2(aq)

NaOH(aq)+HNO3(aq)→H2O(l)+NaNO3(aq)

Na3PO4(aq)+ZnCl2(aq)→Zn3(PO4)2(s)+NaCl(aq)

Respuesta :

The net ionic equation shows the species that underwent a change in the reaction.

What is the net ionic equation?

The net ionic equation shows the species that underwent a change in the reaction. Let us now write the complete ionic and net ionic equations for each reaction.

1) HCl(aq)+LiOH(aq)→H2O(l)+LiCl(aq)

H^+(aq) + Cl^-(aq) + Li^+(aq) + OH^-(aq) -----> H2O(l) +  Li^+(aq) + Cl^-(aq)

H^+(aq) +  OH^-(aq) -----> H2O(l)

2) CaS(aq)+BaCl2(aq)→BaS(s)+CaCl2(aq)

Ca^2+(aq) + S^2-(aq) + Ba^2+(aq) + 2Cl^-(aq) ------> BaS(s) +  Ca^2+(aq) +  2Cl^-(aq)

Ba^2+(aq) +S^2-(aq)   ------> BaS(s)

3) NaOH(aq)+HNO3(aq)→H2O(l)+NaNO3(aq)

Na^+(aq) +  OH^-(aq) + H^+(aq) + NO3^-(aq) ----->  H2O(l) +  Na^+(aq) +  NO3^-(aq)

OH^-(aq) + H^+(aq) ----->  H2O(l)

4) Na3PO4(aq)+ZnCl2(aq)→Zn3(PO4)2(s)+NaCl(aq)

6Na^+(aq) + 2PO4^3-(aq) +3 Zn^2+(aq) + 6Cl^-(aq) -----> Zn3(PO4)2(s) + 6Na^+(aq) +  6Cl^-(aq)

2PO4^3-(aq) +3 Zn^2+(aq)  -----> Zn3(PO4)2(s)

Learn more about ionic equations:https://brainly.com/question/15467449

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