The intercepts of y=2(x−7)(x+2) are x = 7 and x = -2 and the standard form is y = 2x^2 - 10x - 28
The function is given as
y=2(x−7)(x+2)
Set the function to 0
2(x−7)(x+2) = 0
Divide by 2
(x−7)(x+2) = 0
Expand
x - 7 = 0 or x + 2 = 0
Solve for x
x = 7 or x = -2
This means that the intercepts of y=2(x−7)(x+2) are x = 7 and x = -2
Also, we have:
y=2(x−7)(x+2)
Expand
y = 2(x^2 - 7x + 2x - 14)
Further, expand
y = 2x^2 - 10x - 28
Hence, the standard form is y = 2x^2 - 10x - 28
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