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Which graph represents the function p(x) = |x – 1|?

On a coordinate plane, an absolute value graph has a vertex at (0, 1).

On a coordinate plane, an absolute value graph has a vertex at (negative 1, 0).

On a coordinate plane, an absolute value graph has a vertex at (0, negative 1).

On a coordinate plane, an absolute value graph has a vertex at (1, 0).

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"On a coordinate plane, an absolute value graph has a vertex at (1, 0)."

Which graph represents the absolute value function?

Remember that for a general absolute value function:

f(x) = |x - a| + b

The vertex is the point (a, b).

In this case we have:

p(x) = |x - 1|

Then the vertex is at the point (1, 0).

That is enough to conclude that the correct option is the last one:

"On a coordinate plane, an absolute value graph has a vertex at (1, 0)."

If you want to learn more about absolute values:

https://brainly.com/question/1782403

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Answer:

Step-by-step explanation:

its b

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