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A block of mass 5 kg slides down an inclined plane that has an angle of 10. If the inclined plane has no friction and the block starts at a height of 0.8 m, how much kinetic energy does the block have when it reaches the bottom? Acceleration due to gravity is g = 9.8 m/s2

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onyebuchinnaji

The kinetic energy of the block  when it reaches the bottom is 39.2 J.

Kinetic energy of the block at the bottom

Apply the principle of conservation of energy.

K.E(bottom) = P.E(top)

P.E(top) = mgh

where;

  • m is mass of the block
  • g is acceleration due to gravity
  • h is the vertical height of fall

P.E(top) = 5 x 9.8 x 0.8

P.E(top) = K.E(bottom) = 39.2 J

Learn more about kinetic energy here: https://brainly.com/question/25959744

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