The rate of heat transfer by the air conditioner using constant specific heat of 1.004kj/kg.K is 15.06 kW.
Rate of heat transfer is the power rating of the machine.
Work done and changes in potential and kinetic energy are neglected since it is a steady state process.
The specific heat in terms of specific heat capacity and temperature change is given as:
[tex]q_{out} = Cp(Ti - Te)[/tex]
[tex]q_{out} = 1.004(30 - 10) = 20.08 kJ/kg \\ [/tex]
The rate of heat transfer, is then determined as follows:
Qout = 0.75 × 20.08 = 15.06 kW
Therefore, the rate of heat transfer by the air conditioner is 15.06 kW.
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