A 16-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 27 N. Starting from rest, the sled attains a speed of 2.7 m/s in 9.1 m. Find the coefficient of kinetic friction between the runners of the sled and the snow.

Respuesta :

The coefficient of kinetic friction between the runners of the sled and the snow will be 0.146.

What is the friction force?

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N), which is defined as the product of the coefficient of friction and normal force.

Given data;

mass(m) =  16-kg

Horizontal force, F= 27 N

Initial velocity,u=0

v is the final velocity = 2.7 m/s

S is the distance traveled = 9.1 m

To find;

μ is the coefficient of kinetic friction between the runners of the sled and the snow

From Newton's third equation of motion;

v² - u² = 2as

2² - 0² =-2(8.5)a

a = 0.2352 m/s²

From Newton's second law of motion :

[tex]\rm F_{net}= ma \\\\ 30 \ N - \mu = 18 \times (0.2352)\\\\ 30 - 4.2336 = \mu (mg)\\\\ 25.7664 = \mu (18)(9.8) \\\\ \mu = 0.146[/tex]

Hence the coefficient of kinetic friction will be 0.146.

To learn more about the friction force refer to the link;

https://brainly.com/question/1714663

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