The coefficient of kinetic friction between the runners of the sled and the snow will be 0.146.
It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N), which is defined as the product of the coefficient of friction and normal force.
Given data;
mass(m) = 16-kg
Horizontal force, F= 27 N
Initial velocity,u=0
v is the final velocity = 2.7 m/s
S is the distance traveled = 9.1 m
To find;
μ is the coefficient of kinetic friction between the runners of the sled and the snow
From Newton's third equation of motion;
v² - u² = 2as
2² - 0² =-2(8.5)a
a = 0.2352 m/s²
From Newton's second law of motion :
[tex]\rm F_{net}= ma \\\\ 30 \ N - \mu = 18 \times (0.2352)\\\\ 30 - 4.2336 = \mu (mg)\\\\ 25.7664 = \mu (18)(9.8) \\\\ \mu = 0.146[/tex]
Hence the coefficient of kinetic friction will be 0.146.
To learn more about the friction force refer to the link;
https://brainly.com/question/1714663
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