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The plates of an isolated parallel plate capacitor are separated by a distance d and carry charge of magnitude q. The distance between the plates is then reduced to d/2. How is the energy stored in the capacitor affected by this change

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Lanuel

The energy stored in the capacitor decreases to one-half (½) of its initial value when the distance between the plates is then reduced to d/2.

The energy stored in a capacitor.

Mathematically, the energy stored in a capacitor can be calculated by using this formula:

U = ½CV² or U = q²/2C

Where:

  • q is the charge.
  • C is the capacitance.
  • V is the potential difference.

Thus, we can logically deduce that the energy stored in the capacitor decreases to one-half (½) of its initial value when the distance between the parallel plate capacitors is reduced to d/2.

Read more on charge here: brainly.com/question/4313738

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