Hello!
Recall the equation for the force experienced by a charged particle in an electric field:
[tex]F_E = qE[/tex]
q = Charge of particle (20 mC)
E = Electric field strength (8 V/m)
We also know that 'Work' is equivalent to the following:
[tex]W = F \cdot d[/tex]
W = Work (J)
F = Force (N)
d = distance (between the plates in this instance, 0.050 m)
If we substitute 'qE' for 'F':
[tex]W = qEd[/tex]
Plug in the given values and solve.
[tex]W = (0.02)(8)(0.05) = \boxed{0.08 J}[/tex]
**Since we are pushing a positive particle towards the positive plate, we are increasing its electric potential energy, so WE are doing positive work on the particle.
