The distance between the shores A and B is 250 meters.
Width of the river= D
Distance covered by boat A and B= a and b
Distance covered by A and B =Width of the river for the first meet.
D = a + b..............(1)
Hence:
b = 100 meters.............(2)
Sum of the distances traveled is 3times with width of the river as they both went 3 times after they first passed.
Second time= 50 meters
Hence:
3a = D+ 50...........(3)
Put the value of equation 2 into equation 1
3 ×100 = D+ 50
D=300-50
D =250 meters
Therefore the distance between the shores A and B is 250 meters.
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