The 31st term of the given sequence will be 129.
An arithmetic sequence is sequence of integers with its adjacent terms differing with one common difference.
[tex]T_n = a + (n-1)d[/tex]
Given sequence;
309, 303, 297,...
The first term, a1 = 309
The common difference, d = 303 - 309 = -6
The 31st term will be
n = 31
[tex]T_n = a + (n-1)d[/tex]
[tex]T_{31} = 309 + (31-1)(-6)\\\\T_{31} = 309 + (30)(-6)\\\\T_{31} = 309 + (-180)\\\\T_{31} = 129[/tex]
Hence, The 31st term of the given sequence will be 129.
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