Answer:
(-2, 1)
Step-by-step explanation:
So assuming this table contains all the zeroes of f(x) and all of them having a multiplicity of 0. This quadratic equation can be defined as
[tex]f(x) = a(x+2)(x-1)[/tex]. So if you look at the top where its f(-3) then f(-2) then f(-1) it appears to be increasing and then somewhere in between f(-1) and f(0) it has a turning point in which it starts decreasing. and then after f(1) it no longer outputs positive values and appears to be going towards negative infinity. So the interval in which f(x) is positive seems to be finite and using this table it appears to be at (-2, 1) and make sure to use parenthesis since at f(-2) and f(1) it's not positive, because 0 is not positive, so it's not included in the interval
