The probability he will get at least 2 hits in the game is 0.470
The batting average is 0.229
In one game he gets 5 at bat
To find the probability he will get at least 2 hits we use binomial distribution.
The binomial distribution is also a Frequency distribution used for the possible no. of successful outcomes in a given no. of trials in each of which there is the same probability of success.
So we have
n = 5
p = 0.299
q = 1 - p
= 0.701
[tex]P(X) = nC_{x} p^x q^(n-x)[/tex]
P(at least 2 hits in the game) = 1 - P(less than 2 hits)
= 1 - P(0) - P(1)
[tex]= 1 - 0.701^5 - 5C1 x 0.299 x 0.701^4[/tex]
= 1 - 0.169 - 0.361
= 0.470
Learn more on binomial distribution probability here:
https://brainly.com/question/10559687
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