The running speed of Jenny willl be 2.5 times the velocity she walks.
The change of distance concerning to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
Condition 1;
She takes 25 minutes to run 1,000 m and walk 1,600 m The total time to run as well as the walk is 25 minutes.
[tex]\rm t = t_r +t_w \\\\ 25 = t_r +t_w[/tex]
As we know that;
Distance = speed × time
[tex]\rm x_r = v_r \times t_r \\\\ t_r = \frac{x_r}{v_r}[/tex]
For walking;
[tex]\rm t_w = \frac{x_w}{v_w}[/tex]
[tex]\rm t = t_r +t_w \\\\ 25 = \frac{x_r}{v_r} +\frac{x_w}{v_w} \\\\ 25 = \frac{1000 \ m}{v_r} +\frac{1600 \ }{v_w} \\\\ 40 v_w +64 v_r = v_rv_w[/tex]
Same as for condition 2;
[tex]\rm 100 v_w + 40 v_r = v_rv_w[/tex]
[tex]\rm 40 v_w +64 v_r =\rm 100 v_w + 40 v_r \\\\ v_r = 2.5 v_w[/tex]
Condition 3;
[tex]\rm d_w = 800 \ m[/tex]
[tex]\rm d_w = v_w \times t_w[/tex]
[tex]\rm t_w = \frac{d_w}{v_w } \\\\ \rm t_w = \frac{800}{v_w } \\\\[/tex]
Hence their running speed of Jenny willl be 2.5 times the velocity at she walks.
To learn more about the velocity, refer to the link: https://brainly.com/question/862972.
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