The probability that a randomly selected PC costs more than 1200 will be 0.006. The least expensive 10% of personal computers cost less than what amount will be 820.8.
The Gaussian distribution is another name for it. The most significant continuous probability distribution is this one. Because the curve resembles a bell, it is also known as a bell curve.
The z-score is given as
z = (x – μ) / σ
Where μ is the mean, σ is the standard deviation, and x is the sample.
The average price of a personal computer (PC) is $949.
If the computer prices are approximately normally distributed and standard deviation is $100.
Then the probability that a randomly selected PC costs more than 1200 will be
z = (1200 – 949) / 100
z = 2.51
Then the probability will be
P(x > 1200) = P(z > 1200)
P(x > 1200) = 1 – P(z < 1200)
P(x > 1200) = 1 – 0.99396
P(x > 1200) = 0.0060366
The least expensive 10% of personal computers cost less than what amount will be
z-value for 10% will be -1.282.
– 1.282 = (x – 949) / 100
– 128.2 = x – 949
x = 820.8
More about the normal distribution link is given below.
https://brainly.com/question/12421652
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