Answer:
A
Step-by-step explanation:
given a quadratic function in standard form
y = ax² + bx + c (a ≠ 0 ) then the x- coordinate of the vertex is
x = - [tex]\frac{b}{2a}[/tex]
y = 2x² + 8x + 1 ← is in standard form
with a = 2 , b = 8 , then
x = - [tex]\frac{8}{4}[/tex] = - 2
substitute x = - 2 into the equation for corresponding y- coordinate
y = 2(- 2)² + 8(- 2) + 1 = 2(4) - 16 + 1 = 8 - 16 + 1 = - 7
vertex = (- 2, - 7 )
