Respuesta :

ujalakhan18

Answer:

[tex]\huge\boxed{\sf (f-g)(x) = 3x\² + 4x - 14}[/tex]

Step-by-step explanation:

Given functions:

  • f(x) = 4x² - 6
  • g(x) = x² - 4x - 8

Solution:

Subtract both functions

(f-g)(x) = 4x² - 6 - (x² - 4x - 8)

(f-g)(x) = 4x² - 6 - x² + 4x - 8

Combine like terms

(f-g)(x) = 4x² - x² + 4x - 6 - 8

(f-g)(x) = 3x² + 4x - 14

[tex]\rule[225]{225}{2}[/tex]

YourHelperAdi

Given: f(x)=4x^2-6f(x)=4x2−6g(x)=x^2-4x-8g(x)=x2−4x−8

To find : (f-g)(x)

(f-g)(x)=f(x)-g(x)(f−g)(x)=f(x)−g(x)

(4x^2-6)-(x^2-4x-8)

Using Distributive property:-

4x^2-6-x^2+4x+8

4x^2-x^2+4x+8-6

Combine like term

3x^2+4x+2

(f-g)(x)=3x^2+4x+2

Hence, The composite function is (f-g)(x)=3x^2+4x+2

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