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An open bed truck is moving at 20 m/s and comes to a stop. A 100 kg crate sitting in the back of the truck remains at rest in the truck bed. How much work was done by friction to keep the crate from moving
as the truck came to a stop?
[?] J

An open bed truck is moving at 20 ms and comes to a stop A 100 kg crate sitting in the back of the truck remains at rest in the truck bed How much work was done class=

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onyebuchinnaji

The work done was done by friction to keep the crate from moving as the truck came to a stop is 20,000 J.

Work done by friction to prevent the crate from moving

The work done is determined by applying the principle of conservation of energy.

W = K.E

W = ¹/₂mv²

where;

  • m is mass of crate
  • v is speed of the crate with respect to the truck = 20 m/s

W = ¹/₂(100)(20²)

W = 20,000 J

Thus, the work done was done by friction to keep the crate from moving as the truck came to a stop is 20,000 J.

Learn more about work done here: https://brainly.com/question/8119756

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