Respuesta :

diviz2006

Answer: [tex]340gAgNO_{3}[/tex].

Explanation:

You will need to create a stoichiometric equation with the information given. The formula is in the problem and so are the molar masses. I will add and plug in the data for you below.

[tex]24gMg*\frac{1molMg}{24gMg} *\frac{2molAgNO_{3} }{1molMg} *\frac{170gAgNO_{3}}{1molAgNO_{3}} =340gAgNO_{3}[/tex]

I plugged the numbers into my scientific calculator, which is how I got the answer. I also added the letters in the formula above because you have to be able to cancel them out so you can find your missing data.

Therefore, [tex]340gAgNO_{3}[/tex] would react with 24gMg.

I hope this helps! Pls give brainliest!! :)

[tex]340g AgNO_3[/tex] would react with 24 grams of Mg.

What are moles?

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Create a stoichiometric equation with the information given.

[tex]24g Mg X \frac{1 mol of Mg}{24g Mg} X \frac{2 mol of AgNO_3}{1 mol of Mg} X \frac{170g AgNO_3 }{1 mol AgNO_3} = 340g AgNO_3[/tex]

[tex]340g AgNO_3[/tex]

Hence, [tex]340g AgNO_3[/tex] would react with 24 grams of Mg.

Learn more about moles here:

https://brainly.com/question/8455949

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