From the calculations, the volume of the gas is obtained as 9.3 L
The gas laws show the relationship between the volume, pressure, temperature and the number of moles of a gas.
Given that;
V1 = 10 L
T1 = 0 ºC + 273 = 273 K
V2 = ?
T2 = -20 ºC + 273 = 253 K
It then follows that;
V1/T1 = V2/T2
V1T2 = V2T1
V2 = V1T2/T1
V2 = 10 L * 253 K/273 K
V2 = 9.3 L
If the gas were to be hydrogen, the volume of the gas will decrease even further,
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