a. Work done = 2. 0648 Joules
b. Electrical potential, V = 4. 03 × 10^10 volts
a. Work done = force × distance
Force = density × acceleration due to gravity
Force = 5. 80 × 10
Force = 58 Newton
We have that distance = 3. 56cm = 0. 0356 m
Work done = 58 × 0. 0356
Work done = 2. 0648 Joules
b. The formula for electric potential is given thus,
Electric potential, V = [tex]k\frac{q}{r}[/tex]
r = 0. 0356m
k = Coulomb's constant = [tex]8.98*10^9[/tex]kg⋅m3⋅s−4⋅A−2.
q= 1.60x10^-¹C
substitute into the formula
Electric potential, V = [tex]8. 98[/tex] × [tex]10^9[/tex] × [tex]\frac{1. 6 * 10^-^-1}{0. 0356}[/tex]
Electric potential, V = [tex]8. 98 * 10^9[/tex] × [tex]4. 494[/tex]
Electric potential, V = [tex]4. 03 * 10^1^0[/tex] volts
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