The length of one of the legs says line AC is 58.31.
How do we place a figure in a coordinate plane?
A figure can be placed in a coordinate plane on the graph by determining the coordinate of the vertices.
For the given isosceles triangle with:
- The base length of 60 units and
- A height of 50 units.
The coordinate of the vertices are:
- ∠A = (0,0)
- ∠B = (60, 0)
- ∠C = (30, 50)
The length of one leg is calculated as follows:
[tex]\mathbf{AC= \sqrt{(50-0)^2+(30-0)^2}}}[/tex]
AC = [tex]\mathbf{\sqrt{2500+900}}[/tex]
AC = [tex]\mathbf{\sqrt{3400}}[/tex]
AC = 58.31
Learn more about coordinate planes here:
https://brainly.com/question/10737082
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