The statement that cannot be true is that g cannot be parallel to h (g ║h)
On the plane ,
line b is parallel to line f.
Therefore,
b ║ f
line f is parallel to line g,
Therefore,
f ║ g
line h is perpendicular to line b.
h ⊥ b
Therefore,
Since line h is perpendicular b, line b is perpendicular to h.
b can be parallel to g on the plane.
g cannot be parallel to h because h is perpendicular to b.
h can be perpendicular to f because b is parallel to f.
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