You invest $5,000 into an account where interest compounds continuously at 3.5%. How long will it take your money to double? Round answer to nearest year.

Respuesta :

Answer:

20 years

Step-by-step explanation:

Continuous Compounding Formula

[tex]\large \text{$ \sf A=Pe^{rt} $}[/tex]

where:

  • A = Final amount
  • P = Principal amount
  • e = Euler's number (constant)
  • r = annual interest rate (in decimal form)
  • t = time (in years)

Given:

  • A = $10,000
  • P = $5,000
  • r = 3.5% = 0.035

Substitute the given values into the formula and solve for t:

[tex]\sf \implies 10000=5000e^{0.035t}[/tex]

[tex]\sf \implies \dfrac{10000}{5000}=e^{0.035t}[/tex]

[tex]\sf \implies 2=e^{0.035t}[/tex]

[tex]\sf \implies \ln 2=\ln e^{0.035t}[/tex]

[tex]\sf \implies \ln 2=0.035t\ln e[/tex]

[tex]\sf \implies \ln 2=0.035t(1)[/tex]

[tex]\sf \implies \ln 2=0.035t[/tex]

[tex]\sf \implies t=\dfrac{\ln 2}{0.035}[/tex]

[tex]\implies \sf t=19.80420516...[/tex]

Therefore, it will take 20 years (to the nearest year) for the initial investment to double.