James must mix 60 millilitres of 10% solution and 40 millilitres of 50% solution.
Given that, James needs to mix a 10% acid solution with a 50% acid solution to create 100 millilitres of a 26% solution.
Let the acid solution needs to mix with 10% be x ml and the acid solution needs to mix with 50% will be 100 - x ml.
Now,
10% x + 50% ( 100 - x ) = 26% ×100
⇒[tex]\frac{10x}{100} +\frac{50(100-x)}{100}=\frac{2600}{100}[/tex]
⇒10x + 50( 100 - x ) = 2600
⇒10 x + 5000 - 50x = 2600
⇒10 x - 50 x = 2600-5000
⇒-40 x = -2400
⇒x=60
Therefore, James must mix 60 millilitres of 10% solution and 40 millilitres of 50% solution.
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