You need 450 mL of a 65% alcohol solution. On hand, you have a 10% alcohol mixture. How much of the 10% alcohol mixture and pure alcohol will you need to obtain the desired solution?
You will need___ mL of the 10% solution and_ mL of pure alcohol.

Question

contestada

Respuesta :

jainveenamrata jainveenamrata · Answer 1 · 2022-07-09T07:36:40+02:00

You will need 292.5 mL of the 10% solution and 2925 mL of pure alcohol.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

You require 450 mL of a 65% alcohol solution.

On hand, you have a 10% alcohol mixture.

Then the amount of the 10% alcohol mixture and pure alcohol that you need to obtain the desired solution will be

Let x be the amount of the 10% of alcohol is needed.

Then the equation will be

⇒ 450 · 0.65

⇒ 292.5 mL pure alcohol

Then the alcohol mixture will be

0.1x = 292.5

x = 2925 mL of alcohol mixture

You will need 292.5 mL of the 10% solution and 2925 mL of pure alcohol.

More about the Algebra link is given below.

https://brainly.com/question/953809

#SPJ1